For the reaction $C_{2} H_{6} (g) + n O_{2} ⟶ C O_{2} (g) + H_{2} O (l)$ , the ratio of the coefficients of $C O_{2}$ and $H_{2} O$ is:

1:1

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2:3

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3:2

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1:3

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Solution

The correct option is B
2:3

The balanced equation is: $2 C_{2} H_{6} + 7 O_{2} ⟶ 4 C O_{2} + 6 H_{2} O$ . As you can see - the ratio of the coefficients of $C O_{2}$ and $H_{2} O$ is 4:6 or 2:3.

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Similar questions

For the reaction $C_{2} H_{6} (g) + n O_{2} ⟶ C O_{2} (g) + H_{2} O (l)$ , the ratio of the coefficients of $C O_{2}$ and $H_{2} O$ is:

C_{2} H_{6} (g) + n O_{2} \to C O_{2} (g) + H_{2} O (I)

C O_{2}

H_{2} O

C_{2} H_{6} (g) + n O_{2} (g) \to C O_{2} (g) + H_{2} O (l)

C O_{2}

H_{2} O

C_{2} H_{6} (g) + n O_{2} \to C O_{2} (g) + H_{2} O (I)

C O_{2}

H_{2} O

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