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Question

For the reaction:
$$F{ e }^{ 2+ }(aq)+A{ g }^{ + }(aq)\longrightarrow Ag(s)+F{ e }^{ +3 }(aq)$$

Predict which change will decrease the cell voltage?


A
Increase the amount of Ag
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B
Decrease the concentration of Ag+
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C
Increase the concentration of Fe+3
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D
Both B and C
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Solution

The correct option is B Increase the concentration of $$F{ e }^{ +3 }$$
$$E_{cell}=E^o_{cell}-\cfrac {2.303RT}{nF}\log \cfrac {[Ag][Fe^{+3}]}{[Fe^{2+}][Ag^+]}$$

Increasing the concentration of $$Fe^{+3}$$ will decrease cell voltage $$(E_{cell})$$ .

Chemistry

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