Question

# For the reaction:$$F{ e }^{ 2+ }(aq)+A{ g }^{ + }(aq)\longrightarrow Ag(s)+F{ e }^{ +3 }(aq)$$Predict which change will decrease the cell voltage?

A
Increase the amount of Ag
B
Decrease the concentration of Ag+
C
Increase the concentration of Fe+3
D
Both B and C

Solution

## The correct option is B Increase the concentration of $$F{ e }^{ +3 }$$$$E_{cell}=E^o_{cell}-\cfrac {2.303RT}{nF}\log \cfrac {[Ag][Fe^{+3}]}{[Fe^{2+}][Ag^+]}$$Increasing the concentration of $$Fe^{+3}$$ will decrease cell voltage $$(E_{cell})$$ .Chemistry

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