CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Secondary Cells

For the react...

Question

For the reaction:
$F e^{2 +} (a q) + A g^{+} (a q) ⟶ A g (s) + F e^{+ 3} (a q)$

Predict which change will decrease the cell voltage?

A

Increase the amount of Ag

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

Decrease the concentration of

A g^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

Increase the concentration of

F e^{+ 3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

Both

B

and

C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Increase the concentration of $F e^{+ 3}$
$E_{c e l l} = E_{c e l l}^{o} - \frac{2.303 R T}{n F} log \frac{[A g] [F e^{+ 3}]}{[F e^{2 +}] [A g^{+}]}$

Increasing the concentration of $F e^{+ 3}$ will decrease cell voltage $(E_{c e l l})$ .

Suggest Corrections

thumbs-up

1

Similar questions

Q. Consider an electrochemical cell in which the following reaction occurs and predict which changes will decreases the cell voltage:

F e^{2 +} (a q) + A g^{+} (a q) \to A g (s) + F e^{3 +} (a q)

(I) decreases the

[A g^{+}]

(II) increases in

[F e^{3 +}]

(III) increase the amount of

A g

Q. Consider an electrochemical cell in which the following reaction occurs :

F e^{2 +} (a q) + A g^{+} (a q) \to A g (s) + F e^{3 +} (a q)

Then how many of following changes will decrease the cell voltage:

(i) Decrease the

[A g^{+}]

(ii) Increase in

[F e^{3 +}]

(III) Increase the amount of

A g

Q. If the concentration of

O H^{-}

ions in the reaction

F e (O H)_{3} (s) ⇌ F e^{+ 3} (a q .) + 3 O H^{-} (a q .)

is decreased upto

\frac{1}{4}

times, then equilibrium concentration of

F e^{+ 3}

will increase upto:

Q. At equimolar concentrations of

F e^{2 +}

F e^{3 +}

[A g^{+}]

be so that the voltage of the galvanic cell made from

A g^{+} / A g

F e^{3 +} / F e^{2 +}

electrodes equals zero? The reaction is

F e^{2 +} + A g^{+} ⇌ F e^{3 +} + A g

. Determine the equilibrium constant at

25^{\circ} C

for the reaction. (Given:

E_{A g^{+} / A g}^{\circ} = 0.799 v o l t

E_{F e^{3 +} / F e^{2 +}}^{\circ} = 0.771 v o l t

Q. A galvanic cell is constructed with

A g^{+} / A g

F e^{3 +} / F e^{2 +}

electrodes. The concentrations of

A g^{+}

at which the e.m.f. of the cell is zero at equimolar concentration of

F e^{2 +}

F e^{3 +}

. Write answer as nearest integer after multiplying it with

10

E_{A g^{+} / A g}^{o} = 0.80 V

E_{F e^{3 +} / F e^{2 +}}^{o} = 0.77 V

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Secondary Cells

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Secondary Cells

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon