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Question

# For the reaction;N2O5⟶2NO2+12O2,given:−d[N2O5]dt=K1[N2O5]−d[NO2]dt=K2[NO2],and −d[O2]dt=K3[O2]The relation between K1,K2,K3 is:

A
2K1=K2=4K3
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B
K1=K2=K3
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C
2K1=4K2=K3
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D
K1=2K2=3K3
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Solution

## The correct option is A 2K1=K2=4K3The given reaction is:-N2O5⟶2NO2+12O2Rate of reaction= −d[N2O5]dt=12d[NO2]dt=2d[O2]dtPutting the value from (ii) & (iii) in (i), we get:-K1[N2O5]=12K2[N2O5]⇒K1=K22⇒K2=2K1 −(A)and from \$(iii), (iv) and (i):-⇒12K2[N2O5]=2K3[N2O5]⇒K2=4K3 −(B)From (A) and (B), we get:-2K1=K2=4K3

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