For the reaction- N 2 O 5 - 2N O 2 - 1 - 2 O 2- - d- N 2 O 5 - dt - k 1 - N 2 O 5 - d- N O 2 - dt - k 2 - N 2 O 5 - d- O 2 - dt - k 3 - N 2 O 5 -The relation in between k 1 - k 2 and k 3 is-

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Elementary and Complex Reactions

For the react...

Question

For the reaction, $N_{2} O_{5} ⟶ 2 N O_{2} + 1 / 2 O_{2}$ ,
$- \frac{d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]$
$\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]$
$\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]$
The relation in between $k_{1}, k_{2}$ and $k_{3}$ is:

2 k_{1} = k_{2} = 4 k_{3}

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k_{1} = k_{2} = k_{3}

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2 k_{1} = 4 k_{2} = k_{3}

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none of the above

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N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2} .

G i v e n : - \frac{d [N_{2} O_{5}]}{d t} = K_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = K_{2} [N_{2} O_{5}]

A n d \frac{d [O_{2}]}{d t} = K_{3} [N_{2} O_{5}]

The relation between $K_{1}, K_{2}$ and $K_{3}$ is

N_{2} O_{5} ⟶ 2 {N O}_{2} + \frac{1}{2} O_{2}

- \frac{d [N_{2} O_{5}]}{d t} = K_{1} [N_{2} O_{5}]

- \frac{d [{N O}_{2}]}{d t} = K_{2} [{N O}_{2}]

- \frac{d [O_{2}]}{d t} = K_{3} [O_{2}]

K_{1}, K_{2}, K_{3}

N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2},

\frac{- d}{d t} [N_{2} O_{5}] = k_{1} [N_{2} O_{5}], \frac{d}{d t} [N O_{2}] = k_{2} [N_{2} O_{5}] a n d

\frac{d}{d t} [O_{2}] = k_{3} [N_{2} O_{3}],

N_{2} O_{5} ⟶ 2 N O_{2} + \frac{1}{2} O_{2}

\frac{- d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]

k_{1}, k_{2}

k_{3}

2 N H_{3} \to N_{2} + 3 H_{2}

- \frac{d [N H_{3}]}{d t} = k_{1} [N H_{3}], \frac{d [N_{2}]}{d t} = k_{2} [N H_{3}], \frac{d [H_{2}]}{d t} = k_{3} [N H_{3}]

k_{1}, k_{2}

k_{3}

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