For the redox reaction $M n O_{4}^{-} + C_{2} O_{4}^{3 +} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$ . The correct whole number stoichiometric coefficients of $M n O_{4}^{-}, C_{2} O_{4}^{3 +}$ and $H^{+}$ are respectively.

2, 5, 16

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16, 5, 2

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5, 16, 2

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2, 16, 5

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Solution

The correct option is A $2, 5, 16$
${M n O}_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} ⟶ {M n}^{2 +} + {e C O}_{2} + H_{2} O$
$\Rightarrow {M n O}_{4}^{-} + 8 H^{+} + {S e}^{-} ⟶ {M n}^{2 +} + 4 H_{2} O} \times 2$
$C_{2} O_{4}^{2 -} ⟶ 2 {C O}_{2} + 2 e^{-} 3 \times 5$
$2 {M n O}_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} ⟶ 4 {M n}^{2 +} + 10 {C O}_{2} + 8 H_{2} O$
coefficient of ${M n O}_{4}^{-}, C_{2} O_{4}^{2 -}, H^{+}$
$2, 5, 16$
Hence,(A) is correct option.

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M n O_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} ⟶ M n^{2 +} + C O_{2} + H_{2} O

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For the redox reaction
MnO−4+C2O−24+H+⟶Mn2++CO2+H2O
the correct coefficients of the reactants MnO−4, C2O2−4 and H+ for the balanced reaction are

2, 5, 16

16, 5, 2

5, 16, 2

2, 16, 5

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