CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

For the resistance network shown in the figure, choose the correct option(s).

28856.png


A
The current through PQ is zero.
loader
B
I1=3A.
loader
C
The potential at S is less than that at Q.
loader
D
I2=2A.
loader

Solution

The correct options are
A The current through PQ is zero.
B The potential at S is less than that at Q.
C $$I_{1} = 3A.$$
D $$I_{2} = 2A.$$
Node  P  and  Q  are  equipotential  and  node  S  and  T  are  equipotential
 due to formation of wheatstone bridge across them
Thus,  no  current  passes  through  PQ  and  ST
$$\displaystyle I_{1}=\dfrac{12}{4}= 3A$$
$$\displaystyle I_{2}=I_{1}(\dfrac{12}{6+12})= 2A$$
now point P and Q are Equipotential and point S and T are equipotential.
from resistor PS current flows from P to S hence voltage of point P is more than voltage of point S , also P is equipotential with Q that's  why Q also has more potential than S.

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image