CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For the strong electrolytes NaOH, NaCl and BaCl2, the molar ionic conductances at infinite dilution are 248 x 104, 126.5 x 104 and 280.0 x 104 s m2mol1,respectively. Calculate 0m for Ba(OH)2.

Open in App
Solution

om(NaOH)=λoNa++λoOH
om(NaCl)=λoNa++λoa
om(BaCl2)=λoBa+2+2λoa
2om(NaOH)2om(NaCl+om(BaCl2)
2λoNa++2λOH(2λoNa++2λoa)+λoBa+2+2λoa
λomBa(OH)2=λoBa+2+2λOH
So om=(2×2482×126.5+280)×104
omBa(OH)2=523×104

1081460_878998_ans_2a3d52fefbb64a97867cab740669ac42.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Kohlrausch Law
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon