For what value of $c$ , the linear equation $2 x + c y = 8$ has equal values of $x$ and $y$ for its solution.

c = \frac{7 - 2 x}{x}, x \neq 0

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c = \frac{8 - 2 x}{x}, x \neq 0

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c = \frac{13 - 2 x}{x}, x \neq 0

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c = \frac{19 - 2 x}{x}, x \neq 0

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Solution

The correct option is B $c = \frac{8 - 2 x}{x}, x \neq 0$
$2 x + c y = 8$
for $x = y$
$2 x + c y = 8 \Rightarrow 2 x + c x = 8$
Then $c = \frac{8 - 2 x}{x}, x \neq 0$

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