Question

For what value of $\lambda$ is the line $(8x+3y-15)+\lambda (3x-8y+12)=0$ parallel to the X-axis?

Answer 1

As the line is parallel to x axis

$\Rightarrow$ Slope $=0$

$\Rightarrow \frac{-(8+3\lambda )}{(3-8\lambda )}=0$

$\Rightarrow \lambda =\frac{-8}{3}$.