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Question

For what value of k,4 is a zero of the polynomial x2x(2k+2)?

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Solution

In the given polynomial f(x)=x2x(2k+2), substitute x=4 as shown below:

f(4)=(4)2(4)(2k+2)=16+42k2=182k

Therefore, f(4)=182k.

Since it is given that x=4 is a zero of the polynomial f(x)=x2x(2k+2), therefore f(4)=0 that is:

182k=02k=18k=182k=9

Hence k=9.


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