Question

# For what value of $$k$$ does the system of equations $$x+2y=3, 5x+ky+7=0$$ haveno solution ? Also, show that there is no value of $$k$$ for which the given system of equations has infinitely many solutions.

Solution

## no solution? also, show that the there is no value of $$k$$ for which the given system of equations has infinitely many solutions.System has no solution:$$\dfrac {a_1}{a_2}=\dfrac {b_1}{b_2}\neq \dfrac {c_1}{c_2}\Rightarrow \dfrac {1}{5}=\dfrac {2}{k}\neq \dfrac {-3}{7}$$$$\therefore k=10$$System has infinitely many solutions:$$\dfrac {a_1}{a_2}=\dfrac {b_1}{b_2}=\dfrac {c_1}{c_2}$$$$\dfrac {1}{5}=\dfrac {2}{k}=\dfrac {-3}{7}$$Which is not at all possible.$$1/5 \neq -3/7$$$$K$$ has no value. MathematicsRS AgarwalStandard X

Suggest Corrections

0

Similar questions
View More

Same exercise questions
View More

People also searched for
View More