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Question

For which of the following, the radius will be same as for hydrogen atom having n=1?

A
He+,n=2
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B
Li2+,n=2
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C
Be3+,n=2
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D
Li2+,n=3
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Solution

The correct option is B Be3+,n=2
rnn2Z

rn=0.529×n2ZA0

For H-atom,
n = 1
Z = 1
r(H)=0.529A0.

and for Be3+,
Z = 4
n = 2
r(Be3+)=0.0529×224A0
r(Be3+)=0.0529A0

Therefore, for the second orbit of Be+3 radius is same as that for 1st orbit of hydrogen.

Hence, option C is correct.

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