Question

# For which of the following, the radius will be same as for hydrogen atom having $$n=1$$?

A
He+,n=2
B
Li2+,n=2
C
Be3+,n=2
D
Li2+,n=3

Solution

## The correct option is B $$Be^{3+}, n=2$$$$r_n\propto \dfrac{n^2}{Z}$$$$r_n = 0.529\times \dfrac{n^2}{Z} A^0$$  For $$H$$-atom, n = 1Z = 1$$r_{(H)} =0.529A^0$$.and for $$Be^{3+}$$, Z = 4n = 2$$r_{(Be^{3+})} = 0.0529\times \dfrac{2^2}{4}A^0$$$$r_{(Be^{3+})} = 0.0529A^0$$Therefore, for the second orbit of $$Be^{+3}$$ radius is same as that for 1st orbit of hydrogen.Hence, option C is correct.Chemistry

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