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Question

For which one of the following input combinations, the given logic circuit gives the output $$Y = 1$$?
671348_452eb5f930ab47d99de3cdd5f90ec240.png


A
A=0,B=0,C=0
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B
A=0,B=1,C=0
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C
A=0,B=1,C=1
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D
A=1,B=1,C=1
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E
A=1,B=0,C=1
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Solution

The correct option is C $$A = 0, B = 1, C = 1$$
The logic circuit is
The output,
$$Y = \overline{\overline {\overline {A} \cdot B} + \overline {C}} = \overline {\overline {\overline {A} \cdot B} \cdot \overline {C}} = \overline {A} \cdot B\cdot C$$
$$[\overline {A + B} = \overline {A} \cdot \overline {B}$$, Demorgan's law]
when $$A = 0, B = 1, C = 1$$, then $$Y = 1 [\because \overline {A} = 1]$$.
707376_671348_ans_bdf681ea34ca4af2ad851e51c7a67795.jpg

Physics

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