Question

# For which reaction at 297 K, the value of KPKC is maximum and minimum respectively. :-a)N2O4⇌2NO2b)2SO2+O2⇌2SO3c)X+Y⇌4Zd)A+3B⇌7C

A
d,c
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B
d,b
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C
c,b
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D
d,a
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Solution

## The correct option is B d,bGiven are four equations in the question.To find: For which reaction KPKC is minimum and maximum respectivelySolution: We know that, KP=KC(RT)ΔngWhere R is gas constant, T is temperature, Δngis change in gaseous moles of reactant and product⇒KPKC=(RT)ΔngSince we want KPKC in each cases, we will compare (RT)Δng in each case.Since R is a constant and T is same in each case, hence we will compare Δng in each case.Therefore in (a), Δng=2−0=2In (b), Δng=2−(2+1)=−1In (c), Δng=4−(1+1)=2In (d), Δng=7−(3+1)=3Since , in (b) Δng=−1∴(RT)Δng is minimumIn (d) Δng=3∴(RT)Δng is maximumHence, option (B) is correct

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