CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For xR{0,1}, let f1(x)=1x, f2(x)=1x and f3(x)=11x be three given functions. If a function, J(x) satisfies (f2oJof1)(x)=f3(x), then J(x) is equal to :

A
f1(x)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
f2(x)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
f3(x)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1xf3(x)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C f3(x)
Given :
f1(x)=1x,
f2(x)=1x,
f3(x)=11x
(f2oJof1)(x)=f3(x) ...(1)

Substituting the values of f1(x) and f3(x) in equation (1), we will get

(f2oJ)(1x)=11x
f2(J(1x))=11x

Substituting J(1x) in the function f2(x) we will get,
1J(1x)=11x
111x=J(1x)
11x1x1=J(1x)

Putting 1x=t,
1tt1=J(t)
t1tt1=J(t)
1t1=J(t)
J(t)=11t
Replacing tx
So , J(x)=11x=f3(x)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon