Byju's Answer
Standard XII
Physics
Relation between Work Done and PE
Force acting ...
Question
Force acting on a particle in a conservative force field is:
(i)
F
=
(
2
^
i
+
3
^
j
)
(ii)
F
=
(
2
x
^
i
+
2
y
^
j
)
(iii)
F
=
(
y
^
i
+
x
^
j
)
Find the potential energy function, if it is zero at origin.
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Solution
U
=
−
∫
F
x
d
x
−
∫
F
y
d
y
(
i
)
U
=
−
∫
2
d
x
−
∫
3
d
y
=
−
2
x
−
3
y
(
i
i
)
U
=
−
∫
2
x
d
x
−
∫
2
y
d
y
=
−
x
2
−
y
2
(
i
i
i
)
U
=
−
∫
y
d
x
−
∫
x
d
y
=
−
∫
d
(
x
y
)
Since,
d
(
x
y
)
=
x
d
y
+
y
d
x
⟹
U
=
−
x
y
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0
Similar questions
Q.
Potential energy for a conservative force
→
F
is given by
U
(
x
,
y
)
=
cos
(
x
+
y
)
. Force acting on a particle at position given by coordinates
(
0
,
π
4
)
is
Q.
If force
→
F
=
y
^
i
+
x
^
j
acting on a particle then find the work done in moving the particle from position
(
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,
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)
to
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,
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)
Q.
Potential energy for a conservative force
→
F
is given by
U
(
x
,
y
)
=
cos
(
x
+
y
)
. Force acting on a particle at position given by coordinates
(
0
,
π
4
)
is
Q.
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→
F
=
(
2
^
i
+
3
^
j
−
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^
k
)
N
is acting on a body at point
(
2
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,
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m
,
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m
)
.
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Q.
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→
v
=
x
^
i
+
y
^
j
moves in a magnetic field
→
B
=
y
^
i
+
x
^
j
. The force acting on the particle has magnitude
F
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