    Question

# Form the pair of linear equations in the following problems, and find their solutions (if they exist) by the elimination method:If we add 1 to the numerator and subtract 1 from the denominator, a fraction reduces to 1. It becomes 12 if we only add 1 to the denominator. What is the fraction?

A
27
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B
35
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C
67
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D
19
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Solution

## The correct option is B 35Let the fraction be xyAs per the question, we havex+1y−1=1 ...(1)xy+1=12 ...(2)From (1) will get⇒x+1=y−1⇒x−y=−2 .....(3)From (2) will get⇒2x=y+1⇒2x−y=1 .....(4)Using Elimination Method:Subtracting (3) and (4) will get⇒x−y−2x+y=−2−1⇒−x=−3⇒x=3Now putting x in (4)⇒2×3−y=1⇒6−y=1⇒−y=−5⇒y=5Hence, x=3,y=5  Suggest Corrections  1      Similar questions
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