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Question

# Formation of polyethylene from calcium carbide takes place as follows:CaC2+2H2O⟶Ca(OH)2+C2H2C2H2+H2⟶C2H4nC2H4⟶(−CH2−CH2−)nThe amount of polyethene obtained from 64.1 kg of CaC2 is:

A
7 kg
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B
14 kg
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C
21 kg
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D
28 kg
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Solution

## The correct option is D 28 kgThe molar mass of CaC2 is 64 g/mol. 64 kg (or 64000 g) of CaC2= 64000 g 64 g/mol= 1000 mol .1000 moles of CaC2= 1000 moles of C2H21000 moles of C2H2= 1000 moles of C2H4The molar mass of C2H4 is 28 g/mol.1000 moles of C2H4= 1000 mol× 28 g/mol= 28000 g or 28 kg. 28 kg of C2H4 will give 28 kg of polythene.Hence, option D is correct.

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