Question

Four added to twice a number yields $\frac{26}{5}$. Find the fractions.

Answer 1

$\begin{array}{l}\text{Let the number be}x.\\ \text{Then, we have:}\\ \Rightarrow 2x+4=\frac{26}{5}\\ \Rightarrow 2x=\frac{26}{5}-4\\ \Rightarrow 2x=\frac{26-20}{5}\\ \Rightarrow x=\frac{{\sout{6}}^3}{\sout{1}{\sout{0}}_5}\\ \Rightarrow x=\frac{3}{5}\\ \therefore \text{The required fraction is}\frac{3}{5}\text{.}\end{array}$