Question

Four bulbs $B_1,B_2,B_3$ and $B_4$ of 100 W each are connected to 220 V main as shown in the figure. The reading in an ideal ammeter will be :

• A. 0.45 A
• B. 0.90 A
• C. 1.35 A
• D. 1.80 A

Answer 1

The correct option is C 1.35 A

Answer is C

Current through each bulb $=100/220=5/11A$

The ammeter reads only the Current which passing through

$B_2{B}_3{B}_4$

Therefore current through ideal ammeter = $3\times 5/11=1.35A$ .