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Question

Four distinct points (2k, 3k), (1, 0), (0, 1) and (0, 0) lie on a circle for
  1. kI
  2. K < 0
  3. 0 < k < 1
  4. For two values of k


Solution

The correct option is C 0 < k < 1
Find the equation of a circle passing through (0, 0), (1, 0), (0, 1)
Put (2K, 3K) in the equation, find K
x2+y2xy=0 has (2K,3K)k=513

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