Question

Four particles, each of mass m, are placed at the four corners of a square of side 'a'. Force exerted by this system on another particle of mass m placed at the midpoint of a side of square is -

A
16Gm255a2
B
16Gm253a2
C
16Gm25a
D
zero

Solution

The correct option is D zero $${F_A} = {{Gm \cdot m} \over {{a^2}}}$$ $$= {{24{m^2}} \over a}$$ $${F_c} = {{4m \cdot m} \over {{a^2}}} = {{24{m^2}} \over a}$$ $${F_c} = {F_A}\& {F_B} = {F_A}$$ So, all are equal and opp.  so zero Physics

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