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Question

Four persons A, B, C and D at the corners of an square of side X move at a constant speed V. Each person maintains a direction towards the person at the next corner. The time, the persons take to meet each other is

A
2X3V
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B
2XV
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C
XV
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D
3X4V
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Solution

The correct option is D XV
Relative velocity of particle 2 along direction of particle 1 is V2/1=V,
The relative distance of particle 1 w.r.t. 2 is X.

Time taken by particle 2 to reach particle 1 is t=XV

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