wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Four point masses 1 kg, 2 kg, 3 kg and 4 kg are located at the corners A, B, C and D respectively of a square ABCD of side 1 m. Find the moment of inertia and radius of gyration of the system about AB as the axis of rotation.

Open in App
Solution

axis of rotation is AB
It is a discrete mass system. We should Individually calculate Moment of Inertia
r= Distance of particle from axis of rotation
for 1 kg particle IA=1×r2=0 ( as r for 1 kg is 0 as it lies on axis)
for 2 kg particle IB=2×r2=0
for 4 kg ID=4×12=4 kg m2
for 2 kg IC=3×12=3 kg m2
So total moment of Inertia =0+0+4+3
I=7 kg m2
Radius of gyration (K)=ITotal mass
K=710
K=710 m.

1432198_1026097_ans_2ed2fb33adb24e0c8f5eb8ff96a85832.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Moment of Inertia
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon