Question

# Four point size bodies each of mass $$m$$ are fixed at four corners of a light square frame of side length $$L$$. The radius of gyration of these four bodies about an axis perpendicular to the plane of frame passing through its centre is:

A
2L
B
2L
C
L2
D
L2

Solution

## The correct option is C $$\dfrac{L}{\sqrt{2}}$$$$I= 4\left (m \left (\dfrac{L}{\sqrt2} \right )^2 \right )$$$$= 2mL^2$$So we have radius of gyration equivalence equation as,$$4mk^2= 2mL^2$$$$k= \dfrac{L}{\sqrt2}$$ Physics

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