CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Four point size bodies each of mass $$m$$ are fixed at four corners of a light square frame of side length $$L$$. The radius of gyration of these four bodies about an axis perpendicular to the plane of frame passing through its centre is:


A
2L
loader
B
2L
loader
C
L2
loader
D
L2
loader

Solution

The correct option is C $$\dfrac{L}{\sqrt{2}}$$
$$I= 4\left (m \left (\dfrac{L}{\sqrt2}  \right )^2 \right )$$
$$= 2mL^2$$
So we have radius of gyration equivalence equation as,
$$4mk^2= 2mL^2$$
$$k= \dfrac{L}{\sqrt2} $$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image