Four resistors of 4 ohm each are connected in parallel, four such combinations are then connected in series. Their total resistance is

12 Ω

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4 Ω

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20 Ω

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16 Ω

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Solution

The correct option is B
4 Ω

Then, four such combination are connected in series R_total = 1 + 1 + 1 +1 = 4 Ω

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