Four thin rods of same mass 'M' and same length 'l', form a square as shown in the figure. Moment of inertia of this system about an axis through centre O and perpendicular to its plane is
A
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B
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C
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D
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Solution
The correct option is A Moment of inertia of rod AB about point P=112Ml2 M.I. of rod AB about point O=Ml212+M(12)2=13Ml2 [by the theorem of parallel axis] and the system consists of 4 rods of similar type so by the symmetry ISystem=43Ml2.