14xy+2xy+34xy+ ___ = 0
Let the term to be filled in the blank be Z.
Then, 14xy+2xy+34xy+Z = 0
⟹ Z=0−14xy−2xy−34xy
⟹ Z=0+(−14−2−34)xy
⟹ Z=−3xy
Simplify 2xy-[4yx-{3xy-(4xy-2xy)}]