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Question

1logxy xyz+1logyz xyz+1logzx xyz=



A

0

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B

1

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C

2

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D

logzx xyz

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Solution

The correct option is C

2


1logxy xyz+1logyz xyz+1logzx xyz=

=logxyz xy+logxyz yz+logxyz xz    [1loga b=logb a] 

=logxyz x2y2z2                loga m+loga n=loga m.n

=logxyz (xyz)2

=2.1=2


Mathematics

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