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Question

1+tan2A1+cot2A =


A

sec2A

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B

-1

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C

cot2A

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D

tan2A

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Solution

The correct option is D

tan2A


1+tan2A1+cot2A

=1+tan2A1+1tan2A

=1+tan2Atan2A+1tan2A

=(1+tan2A)(tan2A)(tan2A+1)

= tan2A.


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