Question

$\frac{2}{b+c}+\frac{2}{c+a}+\frac{2}{a+b}>\frac{9}{a+b+c}$

• A. True
• B. False

Answer 1

Answer: (A)

We know that
$\frac{(a+b{)}^{-1}+(b+c{)}^{-1}+(c+a{)}^{-1}}{3}$
$>{\left[\frac{(a+b+b+c+c+a)}{3}\right]}^{-1}$
or $\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{c+a}>3.\frac{3}{2(a+b+c)}$ etc