2 x-1-x-2-2 x-x-2-1-x-2-4-x-2 - Find the value of x

The correct option is B (6/5) (2x 1)(x+2) 2x(x 2)/(x 2)(x+2) x+2 4(x 2)/(x 2)(x+2) ⇒ 2x^2+4x x 2 2x^2+4x=x+2 4x+8 ⇒ 3x+4x 2= 3x+10 ⇒ 10x=12 ⇒ x= 6/5 ...

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Quantitative Aptitude

Functions

2 x-1/x-2-2 x...

Question

$\frac{2 x - 1}{x - 2} - \frac{2 x}{x + 2} = \frac{1}{x - 2} - \frac{4}{x + 2}$ . Find the value of x.

(3/4)

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(6/5)

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(4/7)

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(1/4)

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Solution

The correct option is B
(6/5)

$\frac{(2 x - 1) (x + 2) - 2 x (x - 2)}{(x - 2) (x + 2)} - \frac{x + 2 - 4 (x - 2)}{(x - 2) (x + 2)} \Rightarrow 2 x^{2} + 4 x - x - 2 - 2 x^{2} + 4 x = x + 2 - 4 x + 8 \Rightarrow 3 x + 4 x - 2 = - 3 x + 10 \Rightarrow 10 x = 12 \Rightarrow x = \frac{6}{5}$

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2x−1x−2−2xx+2=1x−2−4x+2. Find the value of x.

The correct option is B (6/5) (2x−1)(x+2)−2x(x−2)(x−2)(x+2)−x+2−4(x−2)(x−2)(x+2)⇒2x2+4x−x−2−2x2+4x=x+2−4x+8⇒3x+4x−2=−3x+10⇒10x=12⇒x=65​

$\frac{2 x - 1}{x - 2} - \frac{2 x}{x + 2} = \frac{1}{x - 2} - \frac{4}{x + 2}$ . Find the value of x.

The correct option is B
(6/5)

$\frac{(2 x - 1) (x + 2) - 2 x (x - 2)}{(x - 2) (x + 2)} - \frac{x + 2 - 4 (x - 2)}{(x - 2) (x + 2)} \Rightarrow 2 x^{2} + 4 x - x - 2 - 2 x^{2} + 4 x = x + 2 - 4 x + 8 \Rightarrow 3 x + 4 x - 2 = - 3 x + 10 \Rightarrow 10 x = 12 \Rightarrow x = \frac{6}{5}$