2x+34−3<x−43−2
2x+34−3<x−43−22x+3−124<x−4−633(2x+3−12)<4(x−4−6)3(2x−9)<4(x−10)6x−27<4x−406x−4x<−40+272x<−13x<−132∴ The solution set is (−∞,−132).
The expansion of 1(4−3x)12 binomial theorem will
be valid, if