Question

$\frac{(3-k)}{(x+3)}=\frac{(2+5k)}{(x+2)}$.

If k = 4 in the above expression, then what is the value of x?

• A. $\frac{-68}{23}$
• B. $\frac{68}{21}$
• C. $\frac{64}{21}$
• D. $\frac{-64}{23}$

Answer 1

The correct option is A $\frac{-68}{23}$

Step 1 :

Put the value of k in the expression

And simplify the expression with respect to x.

$\frac{-1}{(x+3)}=\frac{22}{(x+2)}$

Step 2 :

Keep variables on one side and constants on the other

-1(x + 2) = 22(x + 3)

-x - 2 = 22x + 66

-23x = 68

$x=\frac{-68}{23}$