Question

$\frac{5}{6}$, $\frac{7}{8}$, $\frac{3}{4}$, $\frac{4}{5}$ arranged in ascending order would be :

• A. $\frac{3}{4}$ < $\frac{5}{6}$ < $\frac{4}{5}$ < $\frac{7}{8}$
• B. $\frac{3}{4}$ > $\frac{4}{5}$ > $\frac{5}{6}$ > $\frac{7}{8}$
• C. $\frac{3}{4}$ < $\frac{4}{5}$ < $\frac{5}{6}$ < $\frac{7}{8}$
• D. $\frac{4}{5}$ < $\frac{3}{4}$ < $\frac{5}{6}$ < $\frac{7}{8}$

Answer 1

The correct option is C

$\frac{3}{4}$ < $\frac{4}{5}$ < $\frac{5}{6}$ < $\frac{7}{8}$

To arrange the given numbers in ascending order we will have to first make the Denominators equal by finding the LCM.

LCM of 6, 8, 4 and 5 is 120

Calculating these numbers converting denominator to 120 we get :

$\frac{5\times 20}{6\times 20}$, $\frac{7\times 15}{8\times 15}$, $\frac{3\times 30}{4\times 30}$, $\frac{4\times 24}{5\times 24}$

$\Rightarrow$ $\frac{100}{120}$, $\frac{105}{120}$, $\frac{90}{120}$, $\frac{96}{120}$

Arranging them in ascending order we get,

$\frac{90}{120}$ < $\frac{96}{120}$ < $\frac{100}{120}$ < $\frac{105}{120}$

$\Rightarrow$ $\frac{3}{4}$ < $\frac{4}{5}$ < $\frac{5}{6}$ < $\frac{7}{8}$