Question

Question 59.
$\frac{8}{18}-\frac{8}{15}=\frac{8}{3}$

Answer 1

False
We have, $\frac{8}{18}-\frac{8}{15}$.

Since they have different denominators, 18 and 15 respectively, they are unlike fractions.

To subtract unlike fractions we first find equivalent fractions with the same denominator that is, we find equivalent fractions of both the unlike fractions which have the same denominator and then subtract the two equivalent fractions.
LCM of 18 and 15
$\begin{array}{cc}2& 18,15\\ 3& 9,15\\ 3& 3,5\\ 5& 1,5\\ & 1,1\end{array}$
$\therefore$ LCM of 18 and 15 = $2\times 3\times 3\times 5=90$
Now, converting the given fractions to equivalent fraction with denominator 90.
$\frac{8}{18}=\frac{8\times 5}{18\times 5}=\frac{40}{90}$ and $\frac{8}{15}=\frac{8\times 6}{15\times 6}=\frac{48}{90}$

$\therefore$ $\frac{40}{90}-\frac{48}{90}=\frac{40-48}{90}=\frac{-8}{90}$