D-dx - x-1 x2-1 x4-1 x8-1 - 15xp-16xq-1 x-1 -2- p-q -

D/dx[x^16 1/x 1 ]=15x^16 16x^15+1/ ( x 1 )^2 ⇒ ( p,q )= ( 16,15 ) ...

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Special Integrals - 3

d/dx [ x+1 ...

Question

$\frac{d}{d x} [(x + 1) (x^{2} + 1) (x^{4} + 1) (x^{8} + 1)] = (15 x^{p} - 16 x^{q} + 1) {(x - 1)}^{- 2}$
$\Rightarrow (p, q) =$

(12, 11)

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(15, 14)

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(16, 14)

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(16, 15)

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Solution

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Similar questions

$\frac{d}{d x} [(x + 1) (x^{2} + 1) (x^{4} + 1) (x^{8} + 1)] = (15 x^{p} - 16 x^{q} + 1) {(x - 1)}^{- 2}$
$\Rightarrow (p, q) =$

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