Sin 18^∘/cos 72^∘ nbsp; nbsp;=sin (90^∘ 72^∘)/cos 72^∘ nbsp; nbsp;=cos 72^∘/cos 72^∘ = 1 nbsp; nbsp;as nbsp; sin (90^∘ nbsp;A) = cos A ...

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Value of Standard Angle(30,60,90)

sin 18∘/cos 7...

Question

$\frac{s i n 18^{\circ}}{c o s 72^{\circ}} =$

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Solution

$\frac{sin 18^{\circ}}{cos 72^{\circ}}$
$= \frac{sin (90^{\circ} - 72^{\circ})}{cos 72^{\circ}}$
$= \frac{cos 72^{\circ}}{cos 72^{\circ}} = 1$ as $s i n (90^{\circ} - A) = c o s A$

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