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Question

Frequency of tuning fork A is 250 Hz. It produces 4 beats / sec with another tuning fork B. When A is filed, the beat frequency is 6 beats / sec. The frequency of B is:


A
264 Hz
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B
254 Hz
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C
250 Hz
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D
246 Hz
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Solution

The correct option is D 246 Hz
As A is filed frequency of A increases which led to increasing in beat frequency. 
So, A has frequency greater than B frequency.
$$\delta=\delta_{A}-\delta _{B}$$
$$4=250-\delta_{B}$$
$$\delta_{B}=246Hz$$

Physics

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