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Question

From 200 mg of CO2, 1021 molecules are removed. How many moles of CO2 are left?

A
2.88×103 mol
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B
7×102 mol
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C
2.88×101 mol
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D
2.8 mol
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Solution

The correct option is A 2.88×103 mol
1 mole of CO2 has a mass of 44 g and contains NA number of molecules.
So, 1021 molecules will be present in =44×10216.023×1023=0.0731 g of CO2=73.1 mg of CO2
Amount of CO2 remained =Initial amountRemoved amount=(20073.1) mg
=126.9 mg
Number of moles CO2 left =amount of CO2 left (g)molar mass (g/mol)=126.9×10344=2.88×103 moles

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