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Question

From $$320\ mg$$ of $$O_2,\, 6.023\times 10^{20}$$ molecules are removed, the no. of moles remained are:


A
9×103 moles
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B
9×102 moles
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C
zero
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D
3×103 moles
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Solution

The correct option is A $$9\times 10^{-3}$$ moles
$$32g$$ of $$O_2= 1 mol= 6.023 \times 10^{23}$$ molecules
$$\therefore 320mg=0.32g=0.01mol=6.023 \times 10^{21}$$
From this $$6.023 \times 10^{20}$$ moles are removed= $$0.001$$ moles
$$\therefore$$ Remaining= $$0.01-0.001= 0.009$$ moles
$$= 9 \times 10^{-3}$$ moles .

Chemistry

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