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Question

# From 440mg of CO2,1020 molecules ofCO2 are removed. The total number of remaining atoms will be?

A
1.51×1020
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B
12.89×1021
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C
1.77×1022
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D
1.46×1023
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Solution

## The correct option is C 1.77×1022Removed molecule =1020 CO2=440 mg=0.44g Molecular weight of CO2=12+32=44 Moles of CO2=0.4444=0.01 Number of molecule = 0.01×6.023×1023 = 6.023×1021 Remaining molecule = initial − removed molecule = 6.023×1021−0.1×1021 = 5.923×1021 Atom remaining = 3× remaining molecule = 3×5.923×1021=1.77×1021 Hence, option(c) is the correct answer.

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