Question

From a right circular cylinder with height $10cm$ and radius of base $6cm$, a right circular cone of the same height and base is removed. Find the volume of the remaining solid

• A. $754.28{cm}^3$
• B. $714.17{cm}^3$
• C. $654.18{cm}^3$
• D. $754.82{cm}^3$

Answer 1

The correct option is A $754.28{cm}^3$

Height of cylinder$=10cm$, base radius$=60cm$

Height of cone$=10cm,$ base radius$=6cm$

Let $V$ be the required volume

volume of remaining solid

$V=\pi r^{2}h-\frac{1}{3}\pi r^{2}h=\frac{2}{3}\pi r^{2}h=\frac{2}{3}\times \frac{22}{7}\times 6\times 6\times 10=\frac{5280}{7}=754.28{cm}^3$