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Question

From a solid cylinder of height 4 cm and radius 3 cm, a conical cavity of height 4 cm and of base radius 3 cm is hollowed out. What is the total surface area of the remaining solid?

A
15π square cm
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B
22π square cm
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C
33π square cm
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D
48π square cm
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Solution

The correct option is D 48π square cm
l=32+42=5
Total surface area of remaining solid
=CSA of cone +CSA of cylinder + area of base of cylinder
=πrl+2πrh+πr2
=πr(l+2h+r)
=π×3×(5+2×4+3)
=π×3×16
=48πcm2

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