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Question

From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm2.

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Solution

Given :
radius (r)=diameter2=1.42=0.7 cm

height (h)=2.4 cm

Total surface area= surface area of cylinder+ surface area of cone2(surface area of above circle).

=2πrh+2πr2+πr2+πrh2+r22πr2

=2πrh+πrh2+r2+πr2

=π(2rh+r2+rh2+r2)

=227(2×0.7×2.4+(0.7)2+0.7(0.7)2+(24)2)

=227(3.36+0.49+1.75)

=227(5.6)

Total surface area=17.6cm2.

Hence, this is the answer.

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