Question

From a solid right circular cylinder with height $10cm$ and radius of the base $6cm$, a right circular cone of the same height and base is removed. Find the volume of the remaining solid. (Take $\pi =3.14$)

Answer 1

It is given that
Height of the cylinder $=10cm$
Radius of the cylinder $=6cm$

We know that

Volume of the remaining solid $=\pi r^{2}h-\frac{1}{3}\pi r^{2}h$

By substituting the values

Volume of the remaining solid $=(\pi \times 6^2\times 10)-(\frac{1}{3}\pi \times 6^2\times 10)$

It can be written as

Volume of the remaining solid $=\frac{2}{3}\pi \times 6^2\times 10$

So we get

Volume of the remaining solid $=\frac{2}{3}\times 3.14\times 360=753.6c{m}^3$

Therefore the volume of the remaining solid is $753.6c{m}^3$