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Question

From a tower of height 20 m two identical particles are projected. One in horizontal direction with velocity 2 m/s. and another one is just dropped. When the second particle hit the ground. Coordinate of C.M w.r.t projection point is:

A
(2,20)
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B
(2,20)
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C
(2,20)
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D
(2,20)
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Solution

The correct option is A (2,20)
Both particles have same vertical velocity i.e zero so they will reach simultaneously.
Taking the projection point at origin and the horizontal direction as x axis we get that both particles will have their
y coordinate as y1=20m=y2
and the x coordinate of second particle will be x2=0(beneath)
and the time taken by the first particle in covering 20m will be t=2hg=2×2010=2sec

Horizontal distance covered in this time will be u×t=2m/s×2s=4meter
so the x coordinate of the first particle will be x1=4m
coordinate of center of mass x=mx1+mx2m+m=2
similarly y=20 so we get center of mass as (2,20)


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