Let, the fare of ticket for station A be Rs. x
and the fare of ticket for station B be Rs.y
2x+3y=77.....(1)
and3x+5y=124.....(2)
Multiplying equation no. (1) by 3 and (2) by 2.
6x+9y=231.....(3)
6x+10y=248.....(4).
−−−
______________
−y=−17
y=17
From (1)2x+3(17)=77
2x=77−51
2x=36
x=13
Thus, fare for station A=Rs. 13
and, fare for station B=Rs. 17.