From the given figure, find the value of a & b respectively.

$120^{\circ}, 60^{\circ}$

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$130^{\circ}, 50^{\circ}$

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$60^{\circ}, 120^{\circ}$

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$100^{\circ}, 80^{\circ}$

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Solution

The correct option is C
$60^{\circ}, 120^{\circ}$

$∠ a = 60^{\circ}$
(Corresponding angles)

$∠ b + 60^{\circ} = 180^{\circ}$
(Linear pair)

$\Rightarrow ∠ b = 180^{\circ} - 60^{\circ} = 120^{\circ} .$

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Similar questions

Question 17

In the given figure, PA|| BC|| DT and AB|| DC. Then, the values of a and b

(a) $60^{\circ}, 120^{\circ}$
(b) $50^{\circ}, 130^{\circ}$
(c) $70^{\circ}, 110^{\circ}$
(d) $80^{\circ}, 100^{\circ}$

In the following figure, if $∠ P = 60^{\circ}$

Find $∠ Q$ .

The following figure shows a quadrilateral with sides AB and DC parallel to each other.

If $∠ A : ∠ D = 4 : 5$

$∠ B = (3 x - 15)^{\circ} a n d$

$∠ C = (4 x + 20)^{\circ}$

Which of the following options is/are correct ?

Find the value of (x+y) from the figure below:

The median for the data is

$\begin{matrix} IQ & 60 - 70 & 70 - 80 & 80 - 90 & 90 - 100 & 100 - 110 & 110 - 120 & 120 - 130 No. of pupils & 2 & 3 & 5 & 16 & 14 & 13 & 7 \end{matrix}$

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From the given figure, find the value of a & b respectively.

The correct option is C 60∘, 120∘ ∠a=60∘ (Corresponding angles) ∠b+60∘=180∘ (Linear pair) ⇒∠b=180∘−60∘=120∘.

The correct option is C
$60^{\circ}, 120^{\circ}$

$∠ a = 60^{\circ}$
(Corresponding angles)

$∠ b + 60^{\circ} = 180^{\circ}$
(Linear pair)

$\Rightarrow ∠ b = 180^{\circ} - 60^{\circ} = 120^{\circ} .$