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Question

From the top of a tower 19.6m high, a ball is thrown horizontally. If the line joining the point of projection to the point where it hits the ground makes an angle of 45 with the horizontal, then the initial velocity of the ball is:

A
9.8ms1
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B
4.9ms1
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C
14.7ms1
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D
2.8ms1
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Solution

The correct option is A 9.8ms1
As the angle is 45 the range and height is going to be equal
vertical motion
Sy=ut+0.5at2
19.6=0+0.5gt2

horizontal motion
Sx=ut
solving above two equations
Sy=0.5g×S2xu2
Sx=Sy
u2=0.5g×19.6=12×9.8×19.6=9.82
u=9.8m/s

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